Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST.
According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes p and q as the lowest node in T that has both p and q as descendants (where we allow a node to be a descendant of itself).”
Given binary search tree: root = [6,2,8,0,4,7,9,null,null,3,5]
Example 1:
1 2 3
Input: root = [6,2,8,0,4,7,9,null,null,3,5], p = 2, q = 8 Output: 6 Explanation: The LCA of nodes 2 and 8 is 6.
Example 2:
1 2 3
Input: root = [6,2,8,0,4,7,9,null,null,3,5], p = 2, q = 4 Output: 2 Explanation: The LCA of nodes 2 and 4 is 2, since a node can be a descendant of itself according to the LCA definition.
Note:
All of the nodes’ values will be unique. p and q are different and both values will exist in the BST.
/* * @lc app=leetcode id=235 lang=java * * [235] Lowest Common Ancestor of a Binary Search Tree */ /** * Definition for a binary tree node. public class TreeNode { int val; TreeNode * left; TreeNode right; TreeNode(int x) { val = x; } } */ classSolution{ public TreeNode lowestCommonAncestor(TreeNode root, TreeNode p, TreeNode q){ if (root == null || p == null || q == null) { returnnull; }